DateDiff Function in VB.NET
How to use DateDiff Function?
Explanation
DateDiff Function
DateDiff Function in Visual Basic.net 2008 is used to return a long value specifying the number of time intrevals between the specified date values.Syntax:
DateAdd(interval,date1,date2)
Example:
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object,
ByVal e As System.EventArgs) Handles MyBase.Load
Dim d1 As Date = #2/4/2009#
Dim d2 As Date = #2/4/2010#
Dim res As Long
res = DateDiff(DateInterval.Day, d1, d2)
MsgBox("The number of time intrevals between the dates
is::" & res)
End Sub
End Class
In the above DateDiff Function example, the time intrevals between two same dates of different years are found using the 'DateDiff()'. The function returns '365'.
