memset() - Buffer Manipulation Function
How to fill memory block in C++?
Explanation
memset() buffer manipulation function fills the first "num" bytes of memory block pointed by the pointer "ptr" to the specified "value". It returns the "ptr" value.
void * memset ( void * ptr, int value, size_t num );
Result :
****pedia.org is an encylopedia
In the above example, "memset()" is used to fill the first "4" bytes of the memory block "str1" with "*". This buffer manipulation function replaces the 4 characters by the symbol.
Syntax:
void * memset ( void * ptr, int value, size_t num );
Example :
| #include <stdio.h> #include <string.h> int main () { char str1[] = "wikipedia.org is an encylopedia"; memset (str1,'*',4); puts (str1); return 0; } |
Result :
****pedia.org is an encylopedia
In the above example, "memset()" is used to fill the first "4" bytes of the memory block "str1" with "*". This buffer manipulation function replaces the 4 characters by the symbol.
