Malloc() Function - Dynamic Allocation
How to allocate memory block using malloc()in C++?
Explanation
Malloc() function, dynamic allocation, returns a pointer to the first byte of memory location of the specified "size" allocated from the heap. If there is no sufficient space the function returns a "NULL" pointer. It performs Dynamic Memory Allocation at run time.
void *malloc(size_t size);
Result :
Memory block allocated
In the above example, first the memory is allocated, then its checked using a "if" loop. Thus to allocate memory block this function can be used. This is the malloc() function of dynamic allocation.
Syntax:
void *malloc(size_t size);
Example :
| #include <stdlib.h> #include <stdio.h> int main () { int * ptr; ptr = (int*) malloc (80*sizeof(int)); if( ptr== NULL ) {printf( "Insufficient memory\n" );} else {printf( "Memory block allocated\n" );} return(0); } |
Result :
Memory block allocated
In the above example, first the memory is allocated, then its checked using a "if" loop. Thus to allocate memory block this function can be used. This is the malloc() function of dynamic allocation.
